Y=3x^2-x+4

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Solution for Y=3x^2-x+4 equation: 



=3Y^2-Y+4

We move all terms to the left:

-(3Y^2-Y+4)=0

We get rid of parentheses

-3Y^2+Y-4=0

a = -3; b = 1; c = -4;
Δ = b2-4ac
Δ = 12-4·(-3)·(-4)
Δ = -47
Delta is less than zero, so there is no solution for the equation

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